JACKSONVILLE, Ala. | Freshman Juan Cruz went 1-for-4 with a two-run home run for the Alabama State baseball in a 7-3 loss to Jacksonville State University at Rudy Abbott Field-Jim Case Stadium on Tuesday.

Sophomore Devin Brooks (1-2) took the loss on the mound for Alabama State (16-18). Junior Will Smith was a bright spot out of the bullpen, going one shutout inning while allowing one hit, walking none and striking out two.

HOW IT HAPPENED

Trailing 2-0, the Hornets first put runs on the board in the fourth inning. Alabama State scored three runs in the frame, highlighted by a two-run homer from Cruz. The Hornets were unable to hold the lead, as Jacksonville State scored five times over the remaining five innings to grab the 7-3 win.

GAME NOTES
» Alabama State's highest scoring inning was the fourth, when it pushed three runs across.
» Alabama State pitchers limited Jacksonville State to just 3-for-16 (.188) with runners in scoring position.
» Alabama State pitchers faced 39 Jacksonville State hitters in the game, allowing seven ground balls and nine fly balls while striking out eight.
» Cruz led the Hornets at the plate, going 1-for-4 with a home run and two RBI.
» Jacksonville State was led offensively by junior Brennen Norton, who went 2-for-4 with a double and two RBI.

UP NEXT: Alabama State travels to Jackson State on Thursday.